Boston Celtics guard Jrue Holiday won the NBA Sportsmanship Award for the second time on Thursday.
Holiday, 34, previously received the Joe Dumars Trophy with the Milwaukee Bucks for the 2020-21 season.
Presented since 1995-96, the award goes to the player who best represents the ideals of sportsmanship on the court.
After each team nominated one player, a panel of league executives selected one finalist from each division. Current NBA players then voted for the winner.
“In my experience, some of the best competitors are those who pair a quiet confidence with humility, show respect for the competition with their own preparation and work, and have the stamina to navigate the ups and downs of a season with grit and perspective,” said Brad Stevens, Celtics president of basketball operations.
“There is no better example of this than Jrue. He is the ultimate teammate and sets a great example for those striving to compete with integrity. His game does his talking, and his impact, on and off the court, goes well beyond his game.”
Holiday is the first Celtics player to win the award. He received a total of 134 first-place votes and 3,046 points in the balloting. Jarrett Allen of the Cleveland Cavaliers (56 first-place votes, 2,704 points) finished second and Kyrie Irving of the Dallas Mavericks (93, 2,640) placed third.
Holiday is also a three-time winner of the Twyman-Stokes Teammate of the Year award and is a finalist for the 2024-25 NBA Social Justice Champion Award. He is a two-time All-Star, two-time NBA champion and two-time Olympic gold medalist.
Holiday averaged 11.1 points, 4.3 rebounds and 3.9 assists in 62 games this season for the Celtics, who are awaiting their opponent in the Eastern Conference semifinals.
–Field Level Media
